200 Miles Is How Many Hours – MathAdvanced MathA ship travels 200 miles at 5 mph. How long did it take? 40 hours 16.7 hours 20 hours
A boat travels 200 miles at 5 miles per hour. How long did it take? 40 hours 16.7 hours 20 hours
200 Miles Is How Many Hours
Unified Method The word “unified” comes from the word “unit” which means one and complete entity. In this method, we find the unit product value from a given number of products and then solve for another number of products.
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Transcribed Caption: A boat travels 200 miles at 5 miles per hour. How long did it take? 40 hours 16.7 hours 20 hours
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Need to dive deeper into the concept behind this app? Look no further. Learn more about this topic, advanced math, and related topics by exploring related questions and additional content below. Presentation on theme: “D=R x T Overview 180 miles 75 miles per hour 5 hours 100 miles” Presentation Transcript:
Motion tasks use the formula distance = speed x time. If the speed is 60 miles per hour and the time is 3 hours, what is the distance? If the distance is 300 miles and the trip takes 4 hours, what was the speed? 180 miles 75 miles per hour If the distance is 200 miles and the speed is 40 miles per hour what is the hour? If the time was 2.5 hours and the speed was 40 miles per hour, what was the distance? 5 hours 100 miles
It helps to find the distance needed to solve the problem. Pay attention to: departure point, direction, time of departure. Draw: Example 1. Two cars start at the same time from the same point and go in opposite directions. A slow car is going 56 miles per hour and a fast car is going 60 miles per hour. In how many hours will they be separated by 464 miles? Slow car (56 mph) Fast car (60 mph) Total starting miles: 464 miles Slow car distance + Fast car distance = 464
Example 2. Two trains depart simultaneously from stations 360 miles apart and head toward each other. The speed of the express train exceeded the speed of the slow train by 10 miles per hour. After two hours, the trains were still 120 miles apart. Find the ticket price for each train. Starting point: 360 miles apart. Direction: Back to Back Starting Time: Equal 120 miles Fast Slow Slow Total Distance: 360 miles Fast Distance + Slow Distance = or Fast Distance + Slow Distance = 240
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Drawing Exercise Example 3. How far can a man drive out of the country at an average speed of 60 miles an hour and return the same way at a speed of 45 miles an hour, given a total of 7 hours of driving? The starting point: the house and the unknown direction: the journey and the return home. Start time: 7 hours in total. Fast start speed, slow speed, fast distance = slow distance
Example 2. Two trains depart simultaneously from stations 360 miles apart and head toward each other. The speed of the express train exceeded the speed of the slow train by 10 miles per hour. After two hours, the trains were still 120 miles apart. Find the ticket price for each train. Enter what you know and find the column Estimate: Slow Speed Time Distance Fast SR+10 Distance Equation SD+FD=240 2 50 100 60 120 =220 Estimate: Slow Speed Fast Speed = Slow Rate + 10
Example 2. Two trains depart simultaneously from stations 360 miles apart and head toward each other. The speed of the express train exceeded the speed of the slow train by 10 miles per hour. After two hours, the trains were still 120 miles apart. Find the ticket price for each train. NEXT Guess Slow Time Slow Time Slow Distance High Speed SR+10 Fast Time Fast Distance Distance Equation SD+FD=240 50 2 100 60 2 120 =220 60 2 120 70 2 140 =260 01 6 2 120 =260 01 6 20 S fare: 55 Express train: 65
Continue to ALGEBRA +10)=240 2x+2(x+10) = 240 2x + 2x + 20 = 240 4x+20 = 240 4x = 220 X = 55 Let x = slow speed Let x + 10= fast speed Answer: Slow train: 55 miles per hour Fast train: 65 miles per hour
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Example 3. How far can a man drive inland at an average speed of 60 miles an hour and return by the same route at a speed of 45 miles an hour, given a total of 7 hours of driving? Plug in what you know and find the equation “Rate Column Slow Rate Time Distance Fast Distance” SD=FD 225=120? 225 60 2 120 45 5 Estimate: Slow Time Slow Time + Fast Time = 7
Example 3. SR ST SD FR FT FD Distance equation SD=FD 45 5 225 60 2 120 225=120 4 180 3 180=180 135 240 135=240 X 45x (7-x)= 6 60 (7-x) 45x =60(7-x) 45x=420-60x 105x=420 X=4 Answer the question! The man drove 180 miles. Let x = slow time. Let 7-x = fast time
Why is it necessary to draw a picture? Where does x go in the guess and check graph? D = r x t To find the distance equation in the Estimate column.
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