# What Is The Molar Mass Of Butane C4h10

What Is The Molar Mass Of Butane C4h10 – Question: Butane, C4H10, reacts with oxygen, O2, to form water, H2O, and carbon dioxide. CO2, as shown in the following chemical equation: 2C4H10 (g) + 13O2 (g) right arrow 10H2O (g) + 8CO2 (g) The coefficients in this equation represent mole ratios. Note that the coefficient of water (10) is five times that of butane (2). Thus, the number of moles of water formed

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## What Is The Molar Mass Of Butane C4h10

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Butane, C4H10, reacts with oxygen, O2, to form water, H2O, and carbon dioxide. CO2, as shown in the following chemical equation: 2C4H10 (g) + 13O2 (g) right arrow 10H2O (g) + 8CO2 (g) The coefficients in this equation represent mole ratios. Note that the coefficient of water (10) is five times that of butane (2). Thus, the number of moles of water formed is five times greater than the number of moles of butane reacted. Also note that the coefficient of butane (2) is one-fourth the coefficient of carbon dioxide (8). So the number of moles of butane that reacts is one quarter of the number of moles of carbon dioxide you produce. But be careful! If you are given the mass of a mixture, you must first convert these proportions to moles before using them. The first step in most stoichiometry problems is to convert the given value from grams to moles. Molar masses, which can be found using the periodic table, serve as conversion factors between grams and moles. What is the molar mass of butane? C4H10? Express your answer numerically in grams per mole using four significant figures. Now that you know the molar masses of the compounds, you are ready to solve stoichiometry problems. In general, a typical strategy. Convert from grams of compound X to moles of compound X using the molar mass of compound X. Convert moles of compound X to moles of compound Y using the coefficients in the balanced chemical equation. Convert from moles of compound Y to grams of compound Y using the molar mass of compound Y. Calculate the mass of water formed when 7.81 g of butane reacts with excess oxygen. Express the mass of water in grams. Calculate the mass of water formed when 7.81 g of butane reacts with excess oxygen. Express the mass of water in grams. Calculate the mass of butane required to produce 64.6 g of carbon dioxide.

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